How do you use the distributive property to rewrite it in factored form #2x-10x#?

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Answer 1 · 2018-03-25T15:27:10

#2x-10x = 2x(1-5)#

#=2x xx (-4)#

The distributive property takes a factor and multiplies it into a bracket.

#3y(2y-5)#

#=6y^2-15y#

If you use the distributive property to factorise, the common factor is divided out of the bracket.

#2x-10x = 2x(1-5)#

#=2x xx (-4)#

Note that they are like terms, so they would usually just be added to give #-8x#