How do you use the distributive property to simplify #4(x+3)#?

2 Answers
Jun 28, 2017

Answer:

#4x+12#

Explanation:

Multiply the number in the front by everything else in the brackets, so you get:
#4*x+4*3#
#=4x+12#

Jun 28, 2017

Answer:

#4x+12#

Explanation:

#"multiply each term in the bracket by "color(red)(4)#

#rArrcolor(red)(4)(x+3)#

#=(color(red)(4)xx x)+(color(red)(4)xx3)#

#=4x+12larrcolor(blue)" simplified"#