How do you use the distributive property to simplify #4(x+3)#?
2 Answers
Jun 28, 2017
Explanation:
Multiply the number in the front by everything else in the brackets, so you get:
Jun 28, 2017
Explanation:
#"multiply each term in the bracket by "color(red)(4)#
#rArrcolor(red)(4)(x+3)#
#=(color(red)(4)xx x)+(color(red)(4)xx3)#
#=4x+12larrcolor(blue)" simplified"#