# How do you use the information provided to write the equation of each circle:Three points on the circle are (-15, -6), (-19,-4), and (-17, -6)?

##### 1 Answer

#### Answer:

Equation of only circle is

#### Explanation:

As there are three points on the circle are

Let us find the equation of perpendicular bisector of points joining

As a point on a perpendicular bisector is equidistant from

or

i.e.

or **....................(1)**

Similarly equation of perpendicular bisector of points joining

or

i.e.

or **....................(2)**

Subtracting equation (2) from (1), we get

Hence center of the circle is

Hence equation of circle is

or

or

graph{x^2+y^2+32x+6y+255=0 [-20.645, -10.645, -6.88, -1.88]}