How do you use the integral test to determine the convergence or divergence of Sigma 1/sqrtn from [1,oo)?
1 Answer
Jul 18, 2018
The series
Explanation:
Let
We have that:
1)
2)
3)
4)
Under these conditions the convergence of the series:
is equivalent to the convergence of the improper integral:
Evaluate the indefinite integral:
and we can see that the integral:
is not convergent.
Then also the series