How do you use the laws of exponents to simplify the expression #(-48x^4y^5z^2)/ (6x^2y^6z^4)#?

Question

1878 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-17T09:30:33

The answer is : #-(8x^2)/(yz^2)#

Let's separate your fraction :

#(-48x^4y^5z^2)/(6x^2y^6z^4) = -48/6 * x^4/x^2 * y^5/y^6 * z^2/z^4#.

Now, we will use the laws of exponents to simplify the last fractions :

# -48/6 * x^4/x^2 * y^5/y^6 * z^2/z^4 = -8 * x^(4-2) * y^(5-6) * z^(2-4)#

#= -8 * x^2 * y^(-1) * z^(-2) = -8*x^2*(1/y)*(1/z^2)#

#=-(8x^2)/(yz^2)#