# How do you use the laws of exponents to simplify the expression 9^-3 / 3^-8?

You may remember that: ${a}^{m} / {a}^{n} = {a}^{m - n}$ and ${a}^{-} m = \frac{1}{a} ^ m$ and ${\left({a}^{m}\right)}^{n} = {a}^{m \cdot n}$
${9}^{-} \frac{3}{3} ^ - 8 = {3}^{8} / {9}^{3} = {3}^{8} / {\left({3}^{2}\right)}^{3} = {3}^{8} / {3}^{6} = {3}^{8 - 6} = {3}^{2} = 9$