How do you use the point on the line and the slope of the line to find three additional points through which the line passes: Point: (5, -6) Slope: m = 1?

Question

28734 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-08T12:25:24

(0,-11), (4,-7) and (6,-5)

We first must construct a linear equation from which these point will lie on. This can be done using the formula

#(y-y_1)=m(x-x_1)#

#m# would be the gradient of the graph, which we have; #m=1#

#x_1 and y_1# are a point on the graph, which we are given; #x_1=5# and #y_1=-6#

Thus, we will get a linear equation of

#(y-(-6))=1(x-(5))#

#(y+6)=(x-5)#

#y=x-11#

graph{y=x-11 [-17.41, 22.59, -15.04, 4.96]}

Now, we can substitute values for x and y to find 3 additional points that lie on this line.