How do you use the properties of logarithms to expand #lnxyz^2#?

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Answer 1 · 2017-01-07T06:27:55

#lnx+lny+2lnz#

Since

#log(ab)=loga+logb#,

then

#ln(xyz^2)=lnx+lny+lnz^2#

and, since

#loga^b=bloga#

then the given expression is:

#lnx+lny+2lnz#