How do you use the properties of logarithms to rewrite(contract) each logarithmic expression #2log_2(64) + log_2(2)#? Precalculus Properties of Logarithmic Functions Functions with Base b 1 Answer George C. Jul 19, 2015 Use #log_a(a^b) = b# to find: #2log_2(64)+log_2(2) = 2*6+1 = 13# Explanation: #log_a(a^b) = b#, so #64=2^6# so #log_2(64) = log_2(2^6) = 6# #2=2^1# so #log_2(2) = log_2(2^1) = 1# So #2log_2(64)+log_2(2) = 2*6+1 = 13# Answer link Related questions What is the exponential form of #log_b 35=3#? What is the product rule of logarithms? What is the quotient rule of logarithms? What is the exponent rule of logarithms? What is #log_b 1#? What are some identity rules for logarithms? What is #log_b b^x#? What is the reciprocal of #log_b a#? What does a logarithmic function look like? How do I graph logarithmic functions on a TI-84? See all questions in Functions with Base b Impact of this question 1497 views around the world You can reuse this answer Creative Commons License