# How do you use the quadratic formula to find both solutions to the quadratic equation 5 - 10x - 3x^2 = 0?

Solve $y = - 3 {x}^{2} - 10 x + 5 = 0$
$D = {d}^{2} = {b}^{2} - 4 a c = 100 + 60 = 160 \to d = \pm 4 \sqrt{10}$
$x = - \frac{5}{3} \pm \frac{4 \sqrt{10}}{6} = \frac{5}{3} \pm \frac{2 \sqrt{10}}{3}$