# How do you use the quadratic formula to find both solutions to the quadratic equation x^2-5x-14=0?

Jul 16, 2015

Solve $y = {x}^{2} - 5 x - 14 = 0.$
$D = {d}^{2} = {b}^{2} - 4 a c = 25 + 56 = 81 - \to$d = +- 9#
$x = - \frac{b}{2 a} \pm \frac{d}{2 a} = \frac{5}{2} \pm \frac{9}{2}$ --> x = 7 and x = -2