Question

How do you use the quadratic formula to solve for y in `3y^2−9y+4=0`?

Answer 1

y= (9`+-` `sqrt33`)/6

Plug in the values in the formula x= (-b `+-` `sqrt(b^2-4ac)`)/2a which represents the solution of a`x^2` +bx +c=0

y= (9`+-` `sqrt(81-4*3*4)`)/ 2*3

= (9`+-` `sqrt33`)/6