# How do you use the quadratic formula to solve for y in 3y^2−9y+4=0?

y= (9$\pm$ $\sqrt{33}$)/6
Plug in the values in the formula x= (-b $\pm$ $\sqrt{{b}^{2} - 4 a c}$)/2a which represents the solution of a${x}^{2}$ +bx +c=0
y= (9$\pm$ $\sqrt{81 - 4 \cdot 3 \cdot 4}$)/ 2*3
= (9$\pm$ $\sqrt{33}$)/6