# How do you use the zero product property to solve (x-5)(2x+7)(3x-4)=0?

• $x - 5 = 0$ if and only if $x = 5$
• $2 x + 7 = 0$ if and only if $x = - \setminus \frac{7}{2}$
• $3 x - 4 = 0$ if and only if $x = \setminus \frac{4}{3}$
So, we conclude that (x−5)(2x+7)(3x−4)=0 if and only if $x$ assumes one of the following values: $5 , - \setminus \frac{7}{2} , \setminus \frac{4}{3}$