# How do you solve the polynomial 24x^2-4x=0?

Jul 31, 2018

$x = 0 \mathmr{and} x = \frac{1}{6}$

#### Explanation:

Here,

$p \left(x\right) = 24 {x}^{2} - 4 x \mathmr{and} x = 0$

$\implies p \left(0\right) = 24 \left(0\right) - 4 \left(0\right) = 0$

So, factoring we get

$24 {x}^{2} - 4 x = 0$

$\therefore 4 x \left(6 x - 1\right) = 0$

$\therefore 4 x = 0 \mathmr{and} 6 x - 1 = 0$

$\therefore x = 0 \mathmr{and} 6 x = 1$

$\therefore x = 0 \mathmr{and} x = \frac{1}{6}$