Question

How do you use transformation to graph the sin function and determine the amplitude and period of `y=sinx-6`?

Answer 1

Amplitude = 1 and Period = `2pi`

Explanation:

Standard form of equation is
`y=sin (bx +c) + d`

Where amplitude = a, Period = -(2pi)/b, phase shift = -c/b.

Given equation is `y=sin(x) - 6`

`a = 1, b = 1, c = 0, d = -6`

Therefore, `amplitude = a = 1`

`Period = (2pi)/b = (2pi)/1 = 2pi`

Phase shift = `-c/b = 0`

Vertical shift `= d = - 6`