# How do you use transformation to graph the sin function and determine the amplitude and period of y=sinx-6?

Oct 30, 2017

Amplitude = 1 and Period = $2 \pi$

#### Explanation:

Standard form of equation is
$y = \sin \left(b x + c\right) + d$

Where amplitude = a, Period = -(2pi)/b, phase shift = -c/b.

Given equation is $y = \sin \left(x\right) - 6$

$a = 1 , b = 1 , c = 0 , d = - 6$

Therefore, $a m p l i t u \mathrm{de} = a = 1$

$P e r i o d = \frac{2 \pi}{b} = \frac{2 \pi}{1} = 2 \pi$

Phase shift = $- \frac{c}{b} = 0$

Vertical shift $= d = - 6$