How do you verify #sin(2pi-theta)=-sintheta#?

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Bdub Share
Mar 8, 2018

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See Below

Explanation:

Use the Property: #sin(x-y)=sinxcosy-cosxsiny#

#LHS: sin(2pi-theta)#

#=sin2picostheta-cos2pisintheta#

#=0*costheta-1*sintheta#

#=0-sin theta#

#=-sintheta#

#=RHS#

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