How do you verify #sin(2pi-theta)=-sintheta#?

Question

33598 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-08T18:34:44

See Below

Use the Property: #sin(x-y)=sinxcosy-cosxsiny#

#LHS: sin(2pi-theta)#

#=sin2picostheta-cos2pisintheta#

#=0*costheta-1*sintheta#

#=0-sin theta#

#=-sintheta#

#=RHS#