Question

How do you verify `Sin[(3pi/2)+theta]= -cos(theta)`?

Answer 1

see below

Explanation:

Use Property; `sin(A+B)=sinAcosB+cosAsinB`

`A=(3pi)/2, B= theta`

Left Side:`sin ((3pi)/2) cos theta+cos ((3pi)/2) sin theta`

`=-1*cos theta+0*sin theta`

`=-cos theta`

`=` Right Side