How do you verify #sin x csc (pi/2 - x)= tan x#?

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Answer 1 · 2016-05-02T21:11:25

see below

Left Side#=sinx csc(pi/2 -x)#

#=sinx xx 1/sin(pi/2 -x)#

#=sinx xx 1/(sin(pi/2) cos x - cos (pi/2) sinx)#

#=sinx xx 1/(1* cosx-0*sinx#

#=sinx xx 1/cos x#

#=sinx/cosx#

#=tanx#

#=#Right Side