How do you verify #sintheta+costheta=(2sin^2theta-1)/(sintheta-costheta)#?

Question

3267 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-12T09:35:14

see below

#sin theta +cos theta=(2sin^2theta-1)/(sin theta-costheta)#

Left Side:#=sin theta +cos theta#

#=(sin theta +cos theta)/1*(sintheta-costheta)/(sintheta-costheta)#

#=(sin^2theta-cos^2theta)/(sin theta -cos theta)#

#=(sin^2theta-(1-sin^2theta))/(sin theta -cos theta)#

#=(sin^2theta-1+sin^2theta)/(sin theta -cos theta)#

#=(sin^2theta+sin^2theta-1)/(sin theta -cos theta)#

#=(2sin^2theta-1)/(sin theta -cos theta)#

#:.=#Right Side