How do you verify #(tanθ – sinθ • cosθ) / (sin²θ) = tanθ#?

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Answer 1 · 2016-05-02T21:35:53

see below

Left Side#=(tan theta-sin theta cos theta)/sin^2 theta#

#=(tan theta-cos theta tan theta * cos theta)/sin^2 theta#-->#sin theta = cos theta tan theta#

#=(tan theta-tan theta cos^2 theta)/sin^2 theta#

#=(tan theta(1-cos^2 theta))/sin^2 theta#

#=(tan theta sin^2 theta)/sin^2 theta#

#=tan theta#

#=#Right Side