How do you verify the identity #sec(A-B)=(secAsecB)/(1+tanAtanB)#? Trigonometry Trigonometric Identities and Equations Sum and Difference Identities 1 Answer Ratnaker Mehta Jun 21, 2017 For Proof, refer to the Explanation. Explanation: #sec(A-B)=1/cos(A-B)=1/(cosAcosB+sinAsinB)# #=1/{cosAcosB(1+(sinAsinB)/(cosAcosB))},# #=1/{cosAcosB(1+tanAtanB)},# #={1/(cosAcosB)}/(1+tanAtanB),# # rArr sec(A-B)=(secAsecB)(1+tanAtanB).# Answer link Related questions What are some sum and difference identities examples? How do you use the sum and difference identities to find the exact value of #cos 15^@#? How do you use the sum and difference identities to find the exact value of cos 75? How do you use the sum and difference identities to find the exact value of tan 105 degrees? How do you apply the sum and difference formula to solve trigonometric equations? How do you evaluate #sin(45)cos(15)+cos(45)sin(15)#? How do you write #cos75cos35+sin75sin 35# as a single trigonometric function? How do you prove that #cos(x-y) = cosxcosy + sinxsiny#? How do you evaluate #cos((3pi)/5)cos((4pi)/15)+sin((3pi)/5)sin((4pi)/15)#? If sinA=4/5 and cosB= -5/13, where A belongs to QI and B belongs to QIII, then find sin(A+B).... See all questions in Sum and Difference Identities Impact of this question 20014 views around the world You can reuse this answer Creative Commons License