How do you verify the identity #sec2theta=(cos^2theta+sin^2theta)/(cos^2theta-sin^2theta)#?

1 Answer
Nov 20, 2016

The equation is verified by applying some trigonometric identities.
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Trigonometric identities used in this exercise:
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#color(red)(cos^2x + sin^2x =1) " " color(red)(Eq1)#
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#color(blue)(cos^2x - sin^2x = cos2x)" "color(blue)(Eq2)#
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#secx=1/ cosx" "Eq3#
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Taking the second side of the equation to prove the equality.
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#(cos^2theta + sin^2theta)/(cos^2theta-sin^2theta)#
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#=color(red)1/(cos^2theta-sin^2theta)" "#applying #color(red)(Eq1)#

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#=color(red)1/color(blue)(cos2theta)" "#applying #color(blue)(Eq2)#
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#=sec2theta" "# Applying #Eq3 " "# for #x=2theta#