# How do you write 1/2x + y = 3 in standard form?

Apr 14, 2017

$y = - \frac{1}{2} x + 3$

#### Explanation:

For this equation, the standard form is $y = m x + c$. We have to rearrange our equation, $\frac{1}{2} x + y = 3$, so it fits this standard form.

We are looking to have only $y$ on one side of the equation, and then a number multiplied by $x$, then another number added on the other side.

Luckily, it is not too complicated in this case. We can simply subtract $\frac{1}{2} x$ from both sides of the equation, giving:

$y = 3 - \frac{1}{2} x$

we can rearrange this to give

$y = - \frac{1}{2} x + 3$

This fits our standard form, $y = m x + c$. This means that in this case, $m = - \frac{1}{2}$, and $c = 3$

Apr 14, 2017

$1 x + 2 y = 6$

#### Explanation:

My understanding of "standard form" for a linear equation is
$\textcolor{w h i t e}{\text{XXX}} A x + B y = C$
with integer constant values for $A , B , C$ and $A \ge 0$

Multiplying both sides of the given equation by $2$ gives the answer above.