How do you write #1/2x + y = 3# in standard form?

2 Answers
Apr 14, 2017

#y = -1/2x +3#

Explanation:

For this equation, the standard form is #y = mx + c#. We have to rearrange our equation, #1/2x + y = 3#, so it fits this standard form.

We are looking to have only #y# on one side of the equation, and then a number multiplied by #x#, then another number added on the other side.

Luckily, it is not too complicated in this case. We can simply subtract #1/2x# from both sides of the equation, giving:

#y = 3 - 1/2x#

we can rearrange this to give

#y = -1/2x + 3#

This fits our standard form, #y = mx + c#. This means that in this case, #m = -1/2#, and #c = 3#

Apr 14, 2017

#1x+2y=6#

Explanation:

My understanding of "standard form" for a linear equation is
#color(white)("XXX")Ax+By=C#
with integer constant values for #A, B, C# and #A>=0#

Multiplying both sides of the given equation by #2# gives the answer above.