# How do you write 10^-2*10^-8 using only positive exponents?

##### 1 Answer
Jan 15, 2017

See entire process below.

#### Explanation:

First, we will use this rule of exponents to combine the terms:

${x}^{\textcolor{red}{a}} \times {x}^{\textcolor{b l u e}{b}} = {x}^{\textcolor{red}{a} + \textcolor{b l u e}{b}}$

${10}^{\textcolor{red}{- 2}} \cdot {10}^{\textcolor{b l u e}{- 8}} \to {10}^{\textcolor{red}{- 2} + \textcolor{b l u e}{- 8}} \to {10}^{-} 10$

Now, we can use this rule of exponents to put this into a term with a positive exponent:

${x}^{\textcolor{red}{a}} = \frac{1}{x} ^ \textcolor{red}{- a}$

${10}^{\textcolor{red}{- 10}} \to \frac{1}{10} ^ \textcolor{red}{- - 10} \to \frac{1}{10} ^ 10$