How do you write 11 3/8 as an improper fraction?

1 Answer
Mar 28, 2018

Answer:

See a solution process below:

Explanation:

One process is:

#11 3/8 = 11 + 3/8 = (8/8 xx 11) + 3/8 = 88/8 + 3/8 = (88 + 3)/8 = 91/8#

Another process is:

  • First, multiply the integer by the denominator: #11 xx 8 = 88#

  • Next, add this result to the numerator: #88 + 3 = 91#

  • Now, put this result over the denominator: #91/8#