How do you write #-12 = 2y + 1/2x# in slope-intercept form?

1 Answer
Tazwar Sikder
Sep 5, 2016

#y = - (1) / (4) x - 6#

Explanation:

We have: #- 12 = 2 y + (1) / (2) x#

In order to write this line's equation in slope-intercept form, we need to express it in terms of #y#:

#=> 2 y = - 12 - (1) / (2) x#

#=> y = - 6 - (1) / (4) x#

#=> y = - (1) / (4) x - 6#

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