Question

How do you write `(16/25)^(3/2)` as radical form?

Answer 1

`(16/25)^(3/2) = +- (sqrt(16)/sqrt(25))^3`

Explanation:

`b^(1/2) = sqrt(b)color(white)("XXX")` and `color(white)("XXX")b^(3/2) = (b^(1/2))^3`

Note
`color(white)("XXX")(+-sqrt(16)/sqrt(25))^3` could be simplified as `+-(4^3)/(5^3) = +- 64/125`

but then it would no longer be in "radical form"