# How do you write 2 3/4 an improper fraction?

Nov 12, 2015

$\frac{11}{4}$.

#### Explanation:

We start with $2 \frac{3}{4}$.
We now multiply the number on the left ($2$), by the denominator ($4$). We get a value of $8$.
We now add, to that value, the numerator ($3$).
We get a value of $11$.
We now put that value over its denominator ($4$).
We get the final answer, $\frac{11}{4}$.

Hope it Helps! :D .

Nov 15, 2015

Another way of looking at it. It is the same thing but in disguise!

#### Explanation:

You need to convert the 2 so that it can be added directly to the $\frac{3}{4}$

It is correct but not normally done to write $2$ as $\frac{2}{1}$

So $2 \frac{3}{4} = \frac{2}{1} + \frac{3}{4}$

We can not add the 2 directly yet!

To be able to add directly we need to change the bottom numbers (Denominator) so that they are both the same.

$\textcolor{b l u e}{\text{Point 1}}$
Anything multiplied by 1 does not have its value changed.

$\textcolor{b l u e}{\text{Point 2}}$
The value of 1 can be written in many forms. For example $\frac{4}{4}$

Multiply $\frac{2}{1}$ by 1 but in the form of $\frac{4}{4}$ giving

$\frac{2}{1} \times \frac{4}{4} + \frac{3}{4}$

$\frac{2 \times 4}{1 \times 4} + \frac{3}{4}$

$\frac{8}{4} + \frac{3}{4}$

Now we can add because the bottom numbers are the same.

$\frac{8 + 3}{4} = \frac{11}{4}$

The bottom number can be thought of as the size of what we are counting (Denominator) and the top number as the count (numerator) When you add you only add counts, not the size.

So it would be wrong to write:

This is false:.....$\textcolor{red}{\frac{8}{4} + \frac{3}{4} = \frac{11}{8} \text{ This is very wrong!!!}}$