# How do you write 21x^2+5x-35=3x^2-4x in standard form?

Dec 7, 2016

$18 {x}^{2} + 9 x - 35 = 0$

#### Explanation:

To get to standard form you must all of the terms must be on one side of the equation and the quadratic must be equal to $0$:

$21 {x}^{2} + 5 x - 35 - 3 {x}^{2} + 4 x = 3 {x}^{2} - 4 x - 3 {x}^{2} + 4 x$

$21 {x}^{2} - 3 {x}^{2} + 5 x + 4 x - 35 = 3 {x}^{2} - 3 {x}^{2} - 4 x + 4 x$

$\left(21 - 3\right) {x}^{2} + \left(5 + 4\right) x - 35 = 0 - 0$

$18 {x}^{2} + 9 x - 35 = 0$