# How do you write 225^(-1/2)=1/15 in Log form?

${225}^{- \frac{1}{2}} = \frac{1}{15}$ is written as ${\log}_{225} \left(\frac{1}{15}\right) = - \frac{1}{2}$ in log form.
${a}^{m} = b$ is written as ${\log}_{a} b = m$ in log form.
Hence ${225}^{- \frac{1}{2}} = \frac{1}{15}$ is written as ${\log}_{225} \left(\frac{1}{15}\right) = - \frac{1}{2}$ in log form.