# How do you write 2s^-5*s^3 using only positive exponents?

Feb 13, 2017

$\frac{2}{s} ^ 2$

#### Explanation:

First, we will use this rule of exponents to combine the $s$ terms:

${x}^{\textcolor{red}{a}} \times {x}^{\textcolor{b l u e}{b}} = {x}^{\textcolor{red}{a} + \textcolor{b l u e}{b}}$

$2 {s}^{\textcolor{red}{- 5}} \cdot {s}^{\textcolor{b l u e}{3}} = 2 {s}^{\textcolor{red}{- 5} + \textcolor{b l u e}{3}} = 2 {s}^{-} 2$

Now, we can use this rule of exponents to eliminate the negative exponent:

${x}^{\textcolor{red}{a}} = \frac{1}{x} ^ \textcolor{red}{- a}$

$2 {s}^{\textcolor{red}{- 2}} = \frac{2}{s} ^ \textcolor{red}{- - 2} = \frac{2}{s} ^ 2$