How do you write #2x^4(4x^2 + 3x + 1)# in standard form?

1 Answer
Jul 12, 2017

Answer:

See a solution process below:

Explanation:

Multiply each term within the parenthesis by the term outside the parenthesis:

#color(red)(2x^4)(4x^2 + 3x + 1) =>#

#(color(red)(2x^4) xx 4x^2) + (color(red)(2x^4) xx 3x) + (color(red)(2x^4) xx 1) =>#

#8x^6 + 6x^5 + 2x^4#