# How do you write 2y+3=-1/3(x-2) in standard form?

Oct 21, 2017

First, standard form is $a x + b y + c = 0$
In this question, we can expend the formula and rearrange it.

You can try it first, and the steps are as follow:

Step 1: Expend it
$2 y + 3 = - \frac{1}{3} x + \frac{2}{3}$

As there are fraction in the formula and it doesn't look good, we can eliminate it by multiplyng 3.

Step 2: Multiply by 3
$6 y + 9 = - 1 x + 2$

Step 3: Rearrange the terms
$x + 6 y + 7 = 0$

And we can get the answer! :)