How do you write 3^-2*3^-8 using only positive exponents?

${3}^{- 2} \setminus \times {3}^{- 8} = \setminus \frac{1}{{3}^{2}} \setminus \times \setminus \frac{1}{{3}^{8}} = \setminus \frac{1}{{3}^{10}}$