# How do you write  (–3r + 4r^2 – 3) – (4r^2 + 6r – 2) in standard form?

Feb 20, 2017

$- 9 r - 1$

#### Explanation:

First remove the individual terms from parenthesis being careful to manage the signs of the individual terms correctly:

$- 3 r + 4 {r}^{2} - 3 - 4 {r}^{2} - 6 r + 2$

Next, group like items:

$4 {r}^{2} - 4 {r}^{2} - 3 r - 6 r - 3 + 2$

Now, combine like items:

$\left(4 - 4\right) {r}^{2} + \left(- 3 - 6\right) r - 1$

$0 {r}^{2} - 9 r - 1$

$- 9 r - 1$