How do you write #(3x^6 - x^4 - 3x^2 - 1) - (9 + 3x^3 + x^2 + x5)# in standard form?

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Answer 1 · 2017-06-28T23:24:28

See a solution process below:

First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

#3w^6 - x^4 - 3x^2 - 1 - 9 - 3x^3 - x^2 - x^5#

Next, group like terms in descending order of their exponents:

#3w^6 - x^5 - x^4 - 3x^3 - 3x^2 - x^2 - 1 - 9#

Now, combine like terms:

#3w^6 - x^5 - x^4 - 3x^3 + (-3 - 1)x^2 + (-1 - 9)#

#3w^6 - x^5 - x^4 - 3x^3 + (-4)x^2 + (-10)#

#3w^6 - x^5 - x^4 - 3x^3 - 4x^2 - 10#