# How do you write 4a^0*7a^-4 using only positive exponents?

Mar 28, 2018

See a solution process below:

#### Explanation:

First, use this rule of exponents to simplify the term on the left:

${a}^{\textcolor{red}{0}} = 1$

$4 {a}^{\textcolor{red}{0}} \cdot 7 {a}^{-} 4 \implies$

$\left(4 \cdot 1\right) \cdot 7 {a}^{-} 4 \implies$

$4 \cdot 7 {a}^{-} 4 \implies$

$28 {a}^{-} 4$

To eliminate the negative exponent use this rule for exponents:

${x}^{\textcolor{red}{a}} = \frac{1}{x} ^ \textcolor{red}{- a}$

$28 {a}^{\textcolor{red}{- 4}} \implies$

$\frac{28}{a} ^ \textcolor{red}{- - 4} \implies$

$\frac{28}{a} ^ \textcolor{red}{4}$