How do you write #(5x - 6) - (3x^3 - 2x^2)# in standard form?
1 Answer
May 16, 2016
Explanation:
The first step is to write the expression without brackets.
#rArr(5x-6)-(3x^3-2x^2)=5x-6-3x^3+2x^2# Writing an answer in standard form means , start with the term that has the highest power of the variable, in this case
#x^3#
followed by terms with decreasing powers until the last term, usually a constant.
#rArr-3x^3+2x^2+5x-6#
