How do you write 6g^-5 using only positive exponents?

1 Answer
Oct 1, 2016

$= \frac{6}{x} ^ 5$

Explanation:

Recall: one of the indices laws: ${x}^{-} m = \frac{1}{x} ^ m$

In $6 {g}^{-} 5$, note that it is only $g$ that has the index of -5.

$6 {g}^{-} 5 = 6 \times {g}^{-} 5$

$= \frac{6}{x} ^ 5$

If it had been $\text{ } {\left(6 g\right)}^{-} 5$

then it means that both 6 and $g$ have the index -5.

${\left(6 g\right)}^{-} 5 = \frac{1}{{\left(6 g\right)}^{5}}$

Be sure to look at the details carefully in Algebra.