How do you write #(6x^3 − 8x − 5) + (3x^3 + 6x + 2)# in standard form?

1 Answer
Jul 2, 2018

#9x^3-2x-3#

Explanation:

Don't forget to get the signs right.
If the sign before the second bracket was a minus then you would have to multiply through by -1.
( i.e. everything in the second brackets would change sign when the brackets are removed)
(+- makes -, -+ makes -, ++ makes +, -- makes +)

Group all terms of the same type together
(#x^3# can only be added to #x^3# etc.)
Note: this is not the same if multipying (e.g.#6x^3*3x^2 = 18x^5#)

Start with unknowns of highest power, end with constants:

#6x^3+3x^3-8x+6x-5+2#

Simplify:

#9x^3-2x-3#