How do you write #7sqrt(z^5)# as an exponential expression?
1 Answer
Jan 14, 2016
If
Explanation:
Suppose
Then by De Moivre's formula we find:
#z^5 = cos(2pi)+i sin(2pi) = 1#
So
However:
#z^(5/2) = cos(pi) + i sin(pi) = -1#
So: