# How do you write -7y - 10x + 11 = 0 in standard form?

Jun 2, 2017

See a solution process below:

#### Explanation:

The standard form of a linear equation is: $\textcolor{red}{A} x + \textcolor{b l u e}{B} y = \textcolor{g r e e n}{C}$

Where, if at all possible, $\textcolor{red}{A}$, $\textcolor{b l u e}{B}$, and $\textcolor{g r e e n}{C}$are integers, and A is non-negative, and, A, B, and C have no common factors other than 1

First, subtract $\textcolor{red}{11}$ from each side of the equation to isolate the $x$ and $y$ terms on the left side of the equation and the constant on the right side of the equation while keeping the equation balanced:

$- 7 y - 10 x + 11 - \textcolor{red}{11} = 0 - \textcolor{red}{11}$

$- 7 y - 10 x + 0 = - 11$

$- 7 y - 10 x = - 11$

Next, rearrange the terms on the left side of the equation so the $x$ term is first:

$- 10 x - 7 y = - 11$

Now, multiply each side of the equation by $\textcolor{red}{- 1}$ so the coefficient of the $x$ term is non-negative while keeping the equation balanced:

$\textcolor{red}{- 1} \left(- 10 x - 7 y\right) = \textcolor{red}{- 1} \times - 11$

$\left(\textcolor{red}{- 1} \times - 10 x\right) + \left(\textcolor{red}{- 1} \times - 7 y\right) = 11$

$\textcolor{red}{10} x + \textcolor{b l u e}{7} y = \textcolor{g r e e n}{11}$