How do you write #8.2 times 10^-4# in standard notation?

2 Answers
May 28, 2016

Answer:

It is 0.00082.

Explanation:

The #10^-4# tells you that you have to write 4 zeros including the first one before the dot. So the number is
#8.2\times10^{-4}=0.00082#

May 28, 2016

Answer:

Emphasising the point made in the other solution

#8.2xx10^(-4)=0.00082#

Explanation:

Given: #8.2xx10^(-4)#

This is the same as

#8.2/(10xx10xx10xx10)#

#=0.82/(10xx10xx10)#

#=0.082/(10xx10)#

#=0.0082/(10)#

#=0.00082#