# How do you write a polynomial function given the real zeroes -1, 2, and 3 and coefficient 1?

Apr 21, 2016

$y = {x}^{3} - 4 {x}^{2} + x + 6$
$y = \left(x + 1\right) \left(x - 2\right) \left(x - 3\right)$
$y = \left(x + 1\right) \left({x}^{2} - 5 x + 6\right)$
$y = {x}^{3} - 5 {x}^{2} + 6 x + {x}^{2} - 5 x + 6$
$y = {x}^{3} - 4 {x}^{2} + x + 6$