How do you write a polynomial function of least degree that has real coefficients, the following given zeros -2,-2,3,-4i and a leading coefficient of 1?

1 Answer
Apr 16, 2018

Answer:

#(x+2)^2(x-(3-4i))(x+(3-4i))#

Explanation:

-2 has a multiplicity of 2 so you can start out with #(x+2)^2# and since #3-4i# is a zero you can multiply it, so: #(x+2)^2(x-(3-4i))# and if you need real coefficients the other zero would have to be #3+4i# because this is the only way to eliminate the #i# in this function so, #(x+2)^2(x-(3-4i))(x+(3-4i))#
Then expand if you need to.