How do you write a polynomial in standard form given the zeros +1, -1 , 3 double root?

1 Answer
May 9, 2016

Answer:

The biquadratic equation with roots #1. -1, 3 and 3# is
#x^4-6x^3+8x^2+6x-9=0#

Explanation:

The biquadratic having factors #(x-1), (x+1)(x+3)(x+3)# is

#f(x)=(x^2-1)(x^2-6x+9)=x^4-6x^3+8x^2+6x-9#

So, the equation with roots 1, -1 anmd 3 double root is

#f(x)=(x^2-1)(x^2-6x+9)=x^4-6x^3+8x^2+6x-9#