How do you write a polynomial in standard form given the zeros x= -1, 3, 5?

1 Answer
Aug 17, 2016

Answer:

#f(x) = x^3-7x^2+7x+15#

Explanation:

Each zero corresponds to a linear factor...

#f(x) = (x-(-1))(x-3)(x-5)#

#=(x+1)(x-3)(x-5)#

#=x^3-7x^2+7x+15#

This is in standard form, with the terms arranged in descending degree.

Any polynomial in #x# with these zeros will be a multiple (scalar or polynomial) of this #f(x)#.