Question

How do you write a polynomial in standard form given the zeros x= 2, 3/5?

Answer 1

`x^2-13/5x+6/5`

Explanation:

The polynomial is the product of two binomials at the degree 1 that are null when `x=2;x=3/5`:

`(x-2)(x-3/5)`

To transform in standard form you would multiply:

`x^2-3/5x-2x+6/5`

and sum the like terms:

`x^2-13/5x+6/5`