# How do you write a polynomial in standard form given the zeros x= 2, 3/5?

Feb 19, 2017

${x}^{2} - \frac{13}{5} x + \frac{6}{5}$

#### Explanation:

The polynomial is the product of two binomials at the degree 1 that are null when x=2;x=3/5:

$\left(x - 2\right) \left(x - \frac{3}{5}\right)$

To transform in standard form you would multiply:

${x}^{2} - \frac{3}{5} x - 2 x + \frac{6}{5}$

and sum the like terms:

${x}^{2} - \frac{13}{5} x + \frac{6}{5}$