Question

How do you write a polynomial in standard form given the zeros x=-3, -4i, 4i?

Answer 1

`p(x)=(x-3)(x+4i)(x-4i)->p(x)=(x-3)(x^2+16)=x^3-3x^2+16x-48`

Explanation:

Write the roots as factors then multiply it out to get the polynomial