How do you write a polynomial in standard form given zeros 3, 2, -1?

1 Answer
Mar 5, 2016

Answer:

#x^3-4x^2+x+6#

Explanation:

Using the fact that if #(x-a)# is a factor of a polynomial, then #a# is a root of that polynomial, we can generate a polynomial with a given set of roots easily by starting from its factored form.

In this case, given the roots #3#, #2#, and #-1#, we would have

#P(x) = (x-3)(x-2)(x-(-1)) = x^3-4x^2+x+6#